x^2-8x+16=-3

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Solution for x^2-8x+16=-3 equation:


Simplifying
x2 + -8x + 16 = -3

Reorder the terms:
16 + -8x + x2 = -3

Solving
16 + -8x + x2 = -3

Solving for variable 'x'.

Reorder the terms:
16 + 3 + -8x + x2 = -3 + 3

Combine like terms: 16 + 3 = 19
19 + -8x + x2 = -3 + 3

Combine like terms: -3 + 3 = 0
19 + -8x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-19' to each side of the equation.
19 + -8x + -19 + x2 = 0 + -19

Reorder the terms:
19 + -19 + -8x + x2 = 0 + -19

Combine like terms: 19 + -19 = 0
0 + -8x + x2 = 0 + -19
-8x + x2 = 0 + -19

Combine like terms: 0 + -19 = -19
-8x + x2 = -19

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -19 + 16

Reorder the terms:
16 + -8x + x2 = -19 + 16

Combine like terms: -19 + 16 = -3
16 + -8x + x2 = -3

Factor a perfect square on the left side:
(x + -4)(x + -4) = -3

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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